10x^2+960x=0

Solution for 10x^2+960x=0 equation:

10x^2+960x=0

a = 10; b = 960; c = 0;
Δ = b2-4ac
Δ = 9602-4·10·0
Δ = 921600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{921600}=960$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(960)-960}{2*10}=\frac{-1920}{20}
=-96
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(960)+960}{2*10}=\frac{0}{20}
=0
$